4v^2-37v+40=0

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Solution for 4v^2-37v+40=0 equation: 



4v^2-37v+40=0

a = 4; b = -37; c = +40;
Δ = b2-4ac
Δ = -372-4·4·40
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$


$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-27}{2*4}=\frac{10}{8}
=1+1/4
$


$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+27}{2*4}=\frac{64}{8}
=8
$

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